JEE Main & Advanced Physics Magnetic Effects of Current / करंट का चुंबकीय प्रभाव Question Bank Biot-savart's Law and Amperes Law

  • question_answer
    In a hydrogen atom, an electron moves in a circular orbit of radius \[5.2\times {{10}^{-11}}\,m\] and produces a magnetic induction of 12.56 T at its nucleus. The current produced by the motion of the electron will be (Given \[{{\mu }_{0}}=4\pi \times {{10}^{-7}}\,Wb/A-m)\] [MP PET 1997]

    A)            \[6.53\times {{10}^{-3}}\,ampere\]                               

    B)            \[13.25\times {{10}^{-10}}\,ampere\]

    C)            \[9.6\times {{10}^{6}}\,ampere\]                                   

    D)            \[1.04\times {{10}^{-3}}\,ampere\]

    Correct Answer: D

    Solution :

                       \[B=\frac{{{\mu }_{0}}}{4\pi }.\frac{2\pi i}{r}\Rightarrow 12.56={{10}^{-7}}\times \frac{2\pi \times i}{5.2\times {{10}^{-11}}}\] \[\Rightarrow i=1.04\times {{10}^{-3}}\,A\]


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