A) 0.56 A
B) 5.6 A
C) 0.28 A
D) 2.8 A
Correct Answer: B
Solution :
\[\frac{{{\mu }_{0}}}{4\pi }\times \frac{2\pi i}{r}=H\Rightarrow \frac{({{10}^{-7}})\times 2\times 3.142\times i}{0.05}=7\times {{10}^{-5}}\] \[\therefore \,i=\frac{7\times 0.05\times {{10}^{-5}}}{2\times 3.142\times {{10}^{-7}}}=\frac{35}{2\times 3.142}=5.6\] amp
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