A) \[2\times {{10}^{-1}}\,T\]
B) \[4.31\times {{10}^{-2}}\,T\]
C) \[6.28\times {{10}^{-4}}\,T\]
D) \[9.81\times {{10}^{-4}}\,T\]
Correct Answer: C
Solution :
\[B=\frac{{{\mu }_{0}}Ni}{2r}=\frac{4\pi \times {{10}^{-7}}\times 1000\times 0.1}{2\times 0.1}=6.28\times {{10}^{-4}}\,T\]
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