A) \[\frac{{{\mu }_{0}}}{4\pi }\frac{2i}{r}(\pi +1)\]
B) \[\frac{{{\mu }_{0}}}{4\pi }\frac{2i}{r}(\pi -1)\]
C) Zero
D) Infinite
Correct Answer: B
Solution :
The given shape is equivalent to the following diagram The field at \[O\] due to straight part of conductor is\[{{B}_{1}}=\frac{{{\mu }_{o}}}{4\pi }.\frac{2i}{r}\]¤. The field at \[O\]due to circular coil is\[{{B}_{2}}=\frac{{{\mu }_{0}}}{4\pi }.\frac{2\pi i}{r}\otimes \]. Both fields will act in the opposite direction, hence the total field at O. i.e. \[B={{B}_{2}}-{{B}_{1}}=\left( \frac{{{\mu }_{o}}}{4\pi } \right)\times (\pi -1)\frac{2i}{r}=\frac{{{\mu }_{o}}}{4\pi }.\frac{2i}{r}(\pi -1)\]You need to login to perform this action.
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