A) \[0.5\times {{10}^{-5}}\,T\]
B) \[1.25\times {{10}^{-4}}\,T\]
C) \[3\times {{10}^{-5}}\,T\]
D) \[4\times {{10}^{-5}}\,T\]
Correct Answer: B
Solution :
\[B=\frac{{{\mu }_{0}}Ni}{2r}=\frac{4\pi \times {{10}^{-7}}\times 50\times 2}{2\times 0.5}=1.25\times {{10}^{-4}}\,T\]
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