A) \[\frac{{{\mu }_{0}}ni}{2r}\]
B) \[\frac{{{\mu }_{0}}}{2\pi }\frac{ni}{r}\]
C) \[\frac{{{\mu }_{0}}ni}{4r}\]
D) \[{{\mu }_{0}}ni\]
Correct Answer: A
Solution :
Magnetic field at the centre of current carrying coil is \[B=\frac{{{\mu }_{0}}}{4\pi }\cdot \frac{2\pi ni}{r}=\frac{{{\mu }_{0}}ni}{2r}\]
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