A) \[4\times {{10}^{-8}}T\]
B) \[8\times {{10}^{-8}}T\]
C) \[12\times {{10}^{-8}}T\]
D) \[16\times {{10}^{-8}}T\]
Correct Answer: B
Solution :
\[B={{10}^{-7}}\frac{2i}{r}={{10}^{-7}}\times \frac{2\times 2}{5}=8\times {{10}^{-8}}\,T\]
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