JEE Main & Advanced Physics Magnetic Effects of Current / करंट का चुंबकीय प्रभाव Question Bank Biot-savart's Law and Amperes Law

  • question_answer
    A straight wire carrying a current 10 A is bent into a semicircular arc of radius 5 cm. The magnitude of magnetic field at the center is                                     [CPMT 2000]

    A)    \[1.5\times {{10}^{-5}}\,T\]                                       

    B)    \[3.14\times {{10}^{-5}}\,T\]

    C)    \[6.28\times {{10}^{-5}}\,T\]                                     

    D)    \[19.6\times {{10}^{-5}}T\]

    Correct Answer: C

    Solution :

       \[B=\frac{{{\mu }_{0}}}{4\pi }\times \frac{\pi i}{r}\Rightarrow B={{10}^{-7}}\times \frac{\pi \times 10}{5\times {{10}^{-2}}}=6.28\times {{10}^{-5}}\,T\]


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