A) \[\text{1}\text{.57}\times \text{10}{{\text{ }}^{\text{-5}}}\,weber/{{m}^{2}}\]
B) \[8.0\times \text{10}{{\text{ }}^{\text{-5}}}\,weber/{{m}^{2}}\]
C) \[2.5\times \text{10}{{\text{ }}^{\text{-5}}}\,weber/{{m}^{2}}\]
D) \[\text{3}.14\times \text{10}{{\text{ }}^{\text{-5}}}\,weber/{{m}^{2}}\]
Correct Answer: B
Solution :
\[B=\frac{{{\mu }_{0}}}{4\pi }\frac{2\pi i}{r}={{10}^{-7}}\times \frac{2\pi \times 2}{0.0157}=8\times {{10}^{-5}}Wb/{{m}^{2}}\]
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