A) \[\frac{{{\mu }_{0}}i}{R}\]
B) \[\frac{{{\mu }_{0}}i}{2R}\]
C) \[\frac{2{{\mu }_{0}}i}{R}\]
D) \[\frac{3{{\mu }_{0}}i}{8R}\]
Correct Answer: D
Solution :
\[B=\frac{{{\mu }_{0}}}{4\pi }\frac{(2\pi -\theta )i}{R}=\frac{{{\mu }_{0}}}{4\pi }\frac{\left( 2\pi -\frac{\pi }{2} \right)\times i}{R}\]\[=\frac{3{{\mu }_{0}}i}{8R}\]
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