A) 2 ´ 10?5 Tesla
B) 4 ´ 10?5 Tesla
C) 8p ´ 10?5 Tesla
D) 4p ´ 10?5 Tesla
Correct Answer: D
Solution :
\[B=\frac{{{\mu }_{0}}}{4\pi }.\frac{2\pi Ni}{r}=\frac{{{10}^{-7}}\times 2\pi \times 100\times 0.1}{5\times {{10}^{-2}}}=4\pi \times {{10}^{-5}}T\]
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