JEE Main & Advanced Chemistry Thermodynamics / रासायनिक उष्मागतिकी Question Bank Bond energy

  • question_answer
    If the bond dissociation energies of \[XY,\,{{X}_{2}}\]and \[{{Y}_{2}}\] (all diatomic molecules) are in the ratio of 1 : 1 : 0.5 and \[{{\Delta }_{f}}H\] for the formation of \[XY\] is \[-200\,kJ\,mol{{e}^{-1}}\]. The bond dissociation energy of \[{{X}_{2}}\] will be         [AIEEE 2005]

    A)                 \[100\,kJ\,mo{{l}^{-1}}\]              

    B)                 \[800\,kJ\,mo{{l}^{-1}}\]

    C)                 \[300\,kJ\,mo{{l}^{-1}}\]              

    D)                 \[400\,kJ\,mo{{l}^{-1}}\]

    Correct Answer: B

    Solution :

               \[XY\xrightarrow{{}}{{X}_{(g)}}+{{Y}_{(g)}}\]; \[\Delta H=+a\,\,kJ/mole\]  ???.(i)                     \[{{X}_{2}}\xrightarrow{{}}2X\]; \[\Delta H=+a\,\,kJ/mole\]           ???. (ii)                     \[{{Y}_{2}}\xrightarrow{{}}2Y\]; \[\Delta H=+0.5\,a\,\,kJ/mole\]       ???.(iii)                     \[\frac{1}{2}\times \text{(ii) }+\frac{\text{1}}{\text{2}}\times \text{(iii)-(i),}\] gives             \[\frac{1}{2}{{X}_{2}}+\frac{1}{2}{{Y}_{2}}\xrightarrow{{}}XY\];              \[\Delta H=\left( +\frac{a}{2}+\frac{0.5}{2}a-a \right)\,\,kJ/mole\]                     \[+\frac{a}{2}+\frac{0.5a}{2}-a=-200\]                                 \[a=800\]


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