A) \[C{{H}_{3}}-C\equiv C-C{{H}_{2}}-CH=CH-CH=C{{H}_{2}}\]
B) \[C{{H}_{3}}-C{{H}_{2}}-CH=CH-C{{H}_{2}}-C\equiv C-CH=C{{H}_{2}}\]
C) \[C{{H}_{3}}-CH=CH-C{{H}_{2}}-C\equiv C-CH=C{{H}_{2}}\]
D) \[C{{H}_{3}}-CH=CH-C{{H}_{2}}-CH=CH-C\equiv CH\]
Correct Answer: D
Solution :
\[\underset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,-\overset{s{{p}^{2}}}{\mathop{CH}}\,=\underset{s{{p}^{2}}}{\mathop{CH}}\,-\overset{s{{p}^{3}}}{\mathop{C{{H}_{2}}}}\,-\underset{s{{p}^{2}}}{\mathop{CH}}\,=\overset{s{{p}^{2}}}{\mathop{CH}}\,-\underset{sp}{\mathop{C}}\,\equiv \underset{sp}{\mathop{CH}}\,\]You need to login to perform this action.
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