A) 4 times
B) 1/4 times
C) 3 times
D) 1/3 times
Correct Answer: D
Solution :
From the ideal gas equation \[\frac{{{P}_{1}}{{V}_{1}}}{{{T}_{1}}}=\frac{{{P}_{2}}{{V}_{2}}}{{{T}_{2}}}\] \[\frac{{{E}_{2}}}{{{E}_{1}}}=\frac{{{P}_{2}}}{{{P}_{1}}}=\frac{{{V}_{1}}}{{{V}_{2}}}\times \frac{{{T}_{2}}}{{{T}_{1}}}=\left( \frac{1}{4} \right)\times \left( \frac{400}{300} \right)=\frac{1}{3}\]Þ\[{{E}_{2}}=\frac{{{E}_{1}}}{3}\] i.e. elasticity will become \[\frac{1}{3}\] times.
You need to login to perform this action.
You will be redirected in
3 sec
