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JEE Main & Advanced Physics Elasticity Question Bank Bulk Modulus

  • question_answer
    If a rubber ball is taken at the depth of 200 m in a pool, its volume decreases by 0.1%. If the density of the water is \[1\times {{10}^{3}}\,kg/{{m}^{3}}\] and \[g=10\,m/{{s}^{2}}\], then the volume elasticity in \[N/{{m}^{2}}\] will be                                           [MP PMT 1991]

    A)                                 \[{{10}^{8}}\]                   

    B)                                 \[2\times {{10}^{8}}\]                

    C)                                 \[{{10}^{9}}\]                   

    D)                                 \[2\times {{10}^{9}}\]                

    Correct Answer: D

    Solution :

                        \[K=\frac{\Delta P}{\Delta V/V}=\frac{h\rho g}{\Delta V/V}=\frac{200\times {{10}^{3}}\times 10}{0.1/100}=2\times {{10}^{9}}\]


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