A) 1 gm
B) 2 gm
C) 4 gm
D) 8 gm
Correct Answer: D
Solution :
Suppose m gm ice melted, then heat required for its melting \[=mL=m\times 80\,cal\] Heat available with steam for being condensed and then brought to 0°C \[=1\times 540+1\times 1\times (100-0)=640\,cal\] Þ Heat lost = Heat taken Þ \[640=m\times 80\] Þ \[m=8\,gm\] Short trick: You can remember that amount of steam (m') at 100°C required to melt m gm ice at 0°C is \[m'=\frac{m}{8}\]. Here, \[m=8\times m'=8\times 1=8\,gm\]You need to login to perform this action.
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