A) 5°C
B) 6°C
C) 7°C
D) 8°C
Correct Answer: A
Solution :
Same amount of heat is supplied to copper and water so \[{{m}_{c}}{{c}_{c}}\Delta {{\theta }_{c}}={{m}_{W}}{{c}_{W}}\Delta {{\theta }_{\,W}}\] Þ \[\Delta {{\theta }_{W}}=\frac{{{m}_{c}}{{c}_{c}}{{(\Delta \theta )}_{c}}}{{{m}_{W}}{{c}_{W}}}=\frac{50\times {{10}^{-3}}\times 420\times 10}{10\times {{10}^{-3}}\times 4200}=5{}^\circ C\]
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