A) 3 : 2
B) 2 : 3
C) 1 : 1
D) 4 : 3
Correct Answer: C
Solution :
Temperature of mixture \[{{\theta }_{mix}}=\frac{{{\theta }_{A}}{{c}_{A}}+{{\theta }_{B}}{{c}_{B}}}{{{c}_{A}}+{{c}_{B}}}\] Þ \[28=\frac{32\times {{c}_{A}}+24\times {{c}_{B}}}{{{c}_{A}}+{{c}_{B}}}\] Þ \[28\,{{c}_{A}}+28{{c}_{B}}=32\,{{c}_{A}}+24\,{{c}_{B}}\] Þ \[\frac{{{c}_{A}}}{{{c}_{B}}}=\frac{1}{1}\]
You need to login to perform this action.
You will be redirected in
3 sec
