A) (2/3)T
B) (8/5)T
C) (3/5)T
D) (3/2)T
Correct Answer: D
Solution :
Temperature of mixture \[{{\theta }_{mix}}=\frac{{{m}_{1}}{{c}_{1}}{{\theta }_{1}}+{{m}_{2}}{{c}_{2}}{{\theta }_{2}}}{{{m}_{1}}{{c}_{1}}+{{m}_{2}}{{c}_{2}}}=\frac{m\times c\times 2T+\frac{m}{2}(2c)T}{m.c+\frac{m}{2}(2c)}=\frac{3}{2}T\]
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