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JEE Main & Advanced Physics Thermometry, Calorimetry & Thermal Expansion Question Bank Calorimetry

  • question_answer
    In supplying 400 calories of heat to a system, the work done will be                         [MP PMT 1989]

    A)            400 joules                              

    B)            1672 joules

    C)            1672 watts                            

    D)            1672 ergs

    Correct Answer: B

    Solution :

               \[W=JH=4.18\times 400=1672\,joule\]


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