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JEE Main & Advanced Physics Thermometry, Calorimetry & Thermal Expansion Question Bank Calorimetry

  • question_answer
    A lead ball moving with a velocity V strikes a wall and stops. If 50% of its energy is converted into heat, then what will be the increase in temperature (Specific heat of lead is S) [RPMT 1996]

    A)            \[\frac{2{{V}^{2}}}{JS}\]  

    B)            \[\frac{{{V}^{2}}}{4JS}\]

    C)            \[\frac{{{V}^{2}}}{J}\]       

    D)            \[\frac{{{V}^{2}}S}{2J}\]

    Correct Answer: B

    Solution :

               \[W=JQ\] Þ \[\frac{1}{2}\left( \frac{1}{2}m{{V}^{2}} \right)=J\times mS\Delta \theta \] Þ \[\Delta \theta =\frac{{{V}^{2}}}{4\,JS}\]


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