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JEE Main & Advanced Physics Thermometry, Calorimetry & Thermal Expansion Question Bank Calorimetry

  • question_answer
    The amount of work, which can be obtained by supplying 200 cal of heat, is [Pb. PET 2001, 03; BHU 2004]

    A)            840 dyne                                

    B)            840 W

    C)            840 erg                                   

    D)            840 J

    Correct Answer: D

    Solution :

               \[W=JQ\] Þ \[W=4.2\times 200=840\,J\].


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