A) 175 gm
B) 300 g
C) 295 gm
D) 375 g
Correct Answer: D
Solution :
Temperature of mixture \[\theta =\frac{{{m}_{1}}{{c}_{1}}{{\theta }_{1}}+{{m}_{2}}{{c}_{2}}{{\theta }_{2}}}{{{m}_{1}}{{c}_{1}}+{{m}_{2}}{{\theta }_{2}}}\] Þ \[32=\frac{{{m}_{1}}\times 0.2\times 40+100\times 0.5\times 20}{{{m}_{1}}\times 0.2+100\times 0.5}\]Þ \[{{m}_{1}}=375\,gm\]
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