2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. Thermometry, Calorimetry & Thermal Expansion

JEE Main & Advanced Physics Thermometry, Calorimetry & Thermal Expansion Question Bank Calorimetry

  • question_answer
    1 g of a steam at 100°C melt how much ice at 0°C? (Latent heat of ice = 80 cal/gm and latent heat of steam = 540 cal/gm)                                                      [Pb. PET 2000]

    A)            1 gm                                        

    B)            2 gm

    C)            4 gm                                        

    D)            8 gm

    Correct Answer: D

    Solution :

                       Suppose m gm ice melted, then heat required for its melting \[=mL=m\times 80\,cal\] Heat available with steam for being condensed and then brought to 0°C \[=1\times 540+1\times 1\times (100-0)=640\,cal\] Þ Heat lost = Heat taken Þ \[640=m\times 80\] Þ \[m=8\,gm\] Short trick: You can remember that amount of steam (m') at 100°C required to melt m gm ice at 0°C is \[m'=\frac{m}{8}\]. Here, \[m=8\times m'=8\times 1=8\,gm\]


You need to login to perform this action.
You will be redirected in 3 sec spinner