A) 32°C
B) 16°C
C) 8°C
D) 24°C
Correct Answer: B
Solution :
For water and ice mixing \[{{\theta }_{\text{mix}}}=\frac{{{m}_{W}}{{\theta }_{W}}-\frac{{{m}_{\,i}}{{L}_{\,i}}}{{{c}_{W}}}}{{{m}_{\,i}}+{{m}_{W}}}\] \[=\frac{20\times 40-\frac{5\times 80}{1}}{5+20}=16{}^\circ C\]
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