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JEE Main & Advanced Physics Thermometry, Calorimetry & Thermal Expansion Question Bank Calorimetry

  • question_answer
    50 gm of ice at 0°C is mixed with 50 gm of water at 80°C, final temperature of mixture will be [DCE 2002]

    A)            0°C

    B)            40°C

    C)            40°C                                         

    D)            4°C

    Correct Answer: A

    Solution :

               \[{{\theta }_{\text{mix}}}=\frac{{{\theta }_{W}}-\frac{{{L}_{i}}}{{{c}_{W}}}}{2}=\frac{80-\frac{80}{1}}{2}=0\]


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