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JEE Main & Advanced Physics Thermometry, Calorimetry & Thermal Expansion Question Bank Calorimetry

  • question_answer
    The relative humidity on a day, when partial pressure of water vapour is \[0.012\times {{10}^{5}}\,Pa\] at 12°C is (take vapour pressure of water at this temperature as \[0.016\times {{10}^{5}}\,Pa\]) [AIIMS 1998]

    A)            70%                                          

    B)            40%

    C)            75%                                          

    D)            25%

    Correct Answer: C

    Solution :

                       Partial pressure of water vapour \[{{P}_{W}}=0.012\times {{10}^{5}}\,Pa\],                    Vapour pressure of water \[{{P}_{V}}=0.016\times {{10}^{5}}\,Pa\].  The relative humidity at a given temperature is given by \[=\frac{\text{Partial pressure of water vapour}}{\text{Vapour pressure of water}}\]      \[=\frac{0.012\times {{10}^{5}}}{0.016\times {{10}^{5}}}=0.75=75%\]


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