JEE Main & Advanced Physics Thermometry, Calorimetry & Thermal Expansion Question Bank Calorimetry

  • question_answer
    Latent heat of 1gm of steam is 536 cal/gm, then its value in joule/kg is                   [RPMT 1999]

    A)            \[2.25\times {{10}^{6}}\]

    B)            \[2.25\times {{10}^{3}}\]

    C)             2.25                                         

    D)            None

    Correct Answer: A

    Solution :

               \[536\frac{cal}{gm}=\frac{536\times 4.2\,J}{{{10}^{-3}}\,kg}=2.25\times {{10}^{6}}\,J/kg\]


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