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JEE Main & Advanced Physics Thermometry, Calorimetry & Thermal Expansion Question Bank Calorimetry

  • question_answer
    50 gm ice at 0°C in insulator vessel, 50g water of 100°C is mixed in it, then final temperature of the mixture is (neglect the heat loss)                                                                  [RPMT 2001]

    A)            10°C                                         

    B)            \[0{}^\circ <<{{T}_{m}}<20{}^\circ C\]

    C)            20°C                                         

    D)            Above 20°C

    Correct Answer: A

    Solution :

               \[{{\theta }_{\text{mix}}}=\frac{{{\theta }_{W}}-\frac{{{L}_{\,i}}}{{{C}_{W}}}}{2}=\frac{100-\frac{80}{1}}{2}=10{}^\circ C\]


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