A) 40°C
B) 60°C
C) 0°C
D) 50°C
Correct Answer: C
Solution :
\[{{\theta }_{\text{mix}}}=\frac{{{m}_{W}}{{\theta }_{W}}-\frac{{{m}_{\,i}}{{L}_{\,i}}}{{{c}_{W}}}}{{{m}_{\,i}}+{{m}_{W}}}\] \[\because \,{{m}_{i}}={{m}_{W}}\]Þ\[{{\theta }_{mix}}=\frac{{{\theta }_{W}}-\frac{{{L}_{i}}}{{{c}_{W}}}}{2}\]\[=\frac{80+0-\frac{336}{4.2}}{2}=0{}^\circ C\]You need to login to perform this action.
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