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JEE Main & Advanced Physics Thermometry, Calorimetry & Thermal Expansion Question Bank Calorimetry

  • question_answer
    300 gm of water at 25°C is added to 100 gm of ice at 0°C. The final temperature of the mixture is [MP PET 2004]

    A)            \[-\frac{5}{3}{}^\circ C\]  

    B)            \[-\frac{5}{2}{}^\circ C\]

    C)            ? 5°C                                        

    D)            0°C

    Correct Answer: D

    Solution :

               \[{{\theta }_{\text{mix}}}=\frac{{{m}_{W}}{{\theta }_{W}}-\frac{{{m}_{\,i}}{{L}_{\,i}}}{{{S}_{W}}}}{{{m}_{\,i}}+{{m}_{W}}}\]\[=\frac{300\times 25-\frac{100\times 80}{1}}{100+300}=-{{1.25}^{o}}C\] Which is not possible. Hence \[{{\theta }_{mix}}={{0}^{o}}C\]


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