A) 31.2°C
B) 32.8°C
C) 36.7°C
D) 38.2°C
Correct Answer: D
Solution :
\[{{\theta }_{\text{mix}}}=\frac{{{m}_{W}}{{\theta }_{W}}-\frac{{{m}_{\,i}}{{L}_{\,i}}}{{{c}_{W}}}}{{{m}_{\,i}}+{{m}_{W}}}\] \[=\frac{100\times 50-10\times \frac{80}{1}}{10+100}\approx 38.2{}^\circ C\]
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