A) 10°C
B) \[0{}^\circ <<{{T}_{m}}<20{}^\circ C\]
C) 20°C
D) Above 20°C
Correct Answer: A
Solution :
\[{{\theta }_{\text{mix}}}=\frac{{{\theta }_{W}}-\frac{{{L}_{\,i}}}{{{C}_{W}}}}{2}=\frac{100-\frac{80}{1}}{2}=10{}^\circ C\]You need to login to perform this action.
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