A) Both the spheres will have the same charge \[Q\]
B) Charge on the \[20\ cm\] sphere will be greater than that on the \[25\ cm\] sphere
C) Charge on the \[25\ cm\] sphere will be greater than that on the \[20\ cm\] sphere
D) Charge on each of the sphere will be \[2Q\]
Correct Answer: C
Solution :
After the connection of wire \[{{V}_{1}}={{V}_{2}}\] \ \[\frac{{{Q}_{1}}}{25}=\frac{{{Q}_{2}}}{20}\] Þ \[\frac{{{Q}_{1}}}{{{Q}_{2}}}=\frac{25}{20}\] Þ \[{{Q}_{1}}>{{Q}_{2}}\]
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