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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Capacitance

  • question_answer
    A parallel plate air capacitor is charged to a potential difference of V. After disconnecting the battery, distance between the plates of the capacitor is increased using an insulating handle. As a result, the potential difference between the plates       [KCET 1999]

    A)            Decreases

    B)                                      Increases

    C)            Becomes zero                     

    D)            Does not change

    Correct Answer: B

    Solution :

     \[V=\frac{Q}{C}\] =\[\frac{Qd}{{{\varepsilon }_{0}}KA}\] Þ \[V\propto d\]


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