2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. Electrostatics & Capacitance

JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Capacitance

  • question_answer
    If a slab of insulating material \[4\times {{10}^{-3}}m\] thick is introduced between the plates of a parallel plate capacitor, the separation between plates has to be increased by \[3.5\times {{10}^{-3}}\,m\] to restore the capacity to original value. The dielectric constant of the material will be [AMU (Med.) 1999]

    A)            6    

    B)            8

    C)            10  

    D)            12

    Correct Answer: B

    Solution :

               \[K=\frac{t}{t-d'}=\frac{4\times {{10}^{-3}}}{4\times {{10}^{-3}}-3.5\times {{10}^{-3}}}=8\]


You need to login to perform this action.
You will be redirected in 3 sec spinner