A) 12.0
B) 10.0
C) 8.0
D) 4.2
Correct Answer: C
Solution :
\[{{C}_{1}}=\frac{{{\varepsilon }_{0}}A}{d}\] and \[{{C}_{2}}=\frac{K{{\varepsilon }_{0}}A}{2d}\] Þ \[\frac{{{C}_{2}}}{{{C}_{1}}}=\frac{K}{2}\] Þ \[\frac{40\times {{10}^{-12}}}{10\times {{10}^{-12}}}=\frac{K}{2}\] Þ K = 8You need to login to perform this action.
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