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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Capacitance

  • question_answer
     A variable condenser is permanently connected to a 100 \[V\] battery. If the capacity is changed from \[2\mu \,F\] to \[10\,\mu \,F\], then change in energy is equal to                           [BHU 2000]

    A)            \[2\times {{10}^{-2}}\,J\]

    B)                                      \[2.5\times {{10}^{-2}}\,J\]

    C)            \[3.5\times {{10}^{-2}}\,J\]

    D)                                      \[4\times {{10}^{-2}}\,J\]

    Correct Answer: D

    Solution :

                       \[\Delta U={{U}_{2}}-{{U}_{1}}=\frac{{{V}^{2}}}{2}({{C}_{2}}-{{C}_{1}})\] \[=\frac{{{(100)}^{2}}}{2}(10-2)\times {{10}^{-6}}=4\times {{10}^{-2}}J\]


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