A) 10 kJ
B) 5 kJ
C) 2 kJ
D) 1 kJ
Correct Answer: D
Solution :
\[U=\frac{1}{2}C{{V}^{2}}=\frac{1}{2}5\times {{10}^{-6}}\times {{(20\times {{10}^{3}})}^{2}}=1kJ\]
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