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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Capacitance

  • question_answer
    64 drops of mercury each charged to a potential of \[10V\]. They are combined to form one bigger drop. The potential of this drop will be (Assume all the drops to be spherical) [MP PET 2003]

    A)            160 V                                       

    B)            80 V

    C)            10 V                                         

    D)            640 V

    Correct Answer: A

    Solution :

               \[V={{n}^{2/3}}v={{(64)}^{2/3}}\times 10=160\,volt\]


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