A) 0.6 Joule
B) 0.06 Joule
C) 0.03 Joule
D) 0.3 Joule
Correct Answer: C
Solution :
\[U=\frac{1}{2}C{{V}^{2}}=\frac{1}{2}\times 6\times {{10}^{-6}}{{(100)}^{2}}=0.03J\]You need to login to perform this action.
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