A) 8
B) 4
C) 6
D) 2
Correct Answer: D
Solution :
\[{{C}_{air}}=\frac{{{\varepsilon }_{0}}A}{d}\], with dielectric slab C¢= \[\frac{{{\varepsilon }_{0}}A}{\left( d-t+\frac{t}{K} \right)}\] Given \[{C}'=\frac{4}{3}C\Rightarrow \]\[\frac{{{\varepsilon }_{0}}A}{\left( d-t+\frac{t}{K} \right)}=\frac{4}{3}\times \frac{{{\varepsilon }_{0}}A}{d}\] \[\Rightarrow K=\frac{4t}{4t-d}=\frac{4(d/2)}{4[(d/2)-d]}=2\]You need to login to perform this action.
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