A) \[32\times {{10}^{-32}}\,Joule\]
B) \[16\times {{10}^{-32}}\,Joule\]
C) \[3.1\times {{10}^{-26}}\,Joule\]
D) \[4\times {{10}^{-10}}\,Joule\]
Correct Answer: A
Solution :
\[W=\frac{{{Q}^{2}}}{2C}=\frac{{{(8\times {{10}^{-18}})}^{2}}}{2\times 100\times {{10}^{-6}}}=32\times {{10}^{-32}}J\]You need to login to perform this action.
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