A) 4
B) 3/2
C) 2
D) 1/2
Correct Answer: A
Solution :
Let \[E=\frac{1}{2}{{C}_{0}}{{V}_{0}}^{2}\,\text{then}\,\text{ }{{E}_{\text{1}}}=2E\] and \[{{E}_{2}}=\frac{E}{2}\] So \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{4}{1}\]You need to login to perform this action.
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