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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Capacitance

  • question_answer
    On increasing the plate separation of a charged condenser, the energy                                 [Kerala PMT 2004]

    A)                    Increases

    B)                                     Decreases

    C)                    Remains unchanged 

    D)            Becomes zero

    Correct Answer: A

    Solution :

               Energy \[U=\frac{1}{2}\frac{{{Q}^{2}}}{C}\] for a charged capacitor charge Q is constant and with the increase in separation C will decrease \[\left( C\propto \frac{1}{d} \right)\], So overall U will increase.


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