A) \[0.0\text{1}\,J/{{m}^{\text{3}}}\]
B) \[0.\text{1}\,J/{{m}^{\text{3}}}\]
C) \[\text{1}.0\,J/{{m}^{\text{3}}}\]
D) \[\text{1}0J/{{m}^{\text{3}}}\]
Correct Answer: B
Solution :
The energy density of parallel plate capacitor is given by \[U=\frac{1}{2}{{\varepsilon }_{0}}{{E}^{2}}=\frac{1}{2}{{\varepsilon }_{0}}{{\left( \frac{V}{d} \right)}^{2}}\] \[=\frac{1}{2}\times 8.85\times {{10}^{-12}}\,{{C}^{2}}/N{{m}^{2}}\times {{\left( \frac{300\,volt}{2\times {{10}^{-3}}m} \right)}^{2}}\]\[=0.1\,J/{{m}^{3}}\]
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