A) Increase by 16 times
B) Increase by 4 times
C) Increase by 2 times
D) Remain the same
Correct Answer: B
Solution :
\[C=\frac{K{{\varepsilon }_{0}}A}{d}\propto \frac{K}{d}\] Hence, \[\frac{{{C}_{1}}}{{{C}_{2}}}=\frac{{{K}_{1}}}{{{K}_{2}}}\times \frac{{{d}_{2}}}{{{d}_{1}}}=\frac{K}{2K}\times \frac{d/2}{d}=\frac{1}{4}\] Therefore, C2 = 4C1
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