JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Capacitance

  • question_answer
    Two metallic spheres of radii \[1\,cm\] and \[2\,cm\] are given charges \[{{10}^{-2}}\,C\] and \[5\times {{10}^{-2}}C\] respectively. If they are connected by a conducting wire, the final charge on the smaller sphere is                                               [CBSE PMT 1995]

    A)                    \[3\times {{10}^{-2}}C\]  

    B)            \[1\times {{10}^{-2}}C\]

    C)                    \[4\times {{10}^{-2}}C\]  

    D)            \[2\times {{10}^{-2}}C\]

    Correct Answer: D

    Solution :

                       \[{{Q}_{1}}={{10}^{-2}}C\], \[{{Q}_{2}}=5\times {{10}^{-2}}C\] Total charge of the system Q = 6 ´ 10?6 C Charge on small sphere     \[Q{{'}_{1}}=\frac{Q\,{{r}_{1}}}{{{r}_{1}}+{{r}_{2}}}=\frac{6\times {{10}^{-2}}\times 1}{1+2}=2\times {{10}^{-2}}C\]


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