A) \[0.02\ Joule\]
B) \[0.04Joule\]
C) \[0.025\,Joule\]
D) \[0.05\,Joule\]
Correct Answer: A
Solution :
\[U=\frac{1}{2}C{{V}^{2}}=\frac{1}{2}\times 4\times {{10}^{-6}}\times {{(100)}^{2}}=0.02\,J\]
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