A) 0
B) . \[F/2\]
C) \[F\]
D) \[2F\]
Correct Answer: B
Solution :
Initially F = qE and \[E=\frac{\sigma }{{{\varepsilon }_{0}}}\] \ \[F=\frac{q\sigma }{{{\varepsilon }_{0}}}\] If one plate is removed, then E becomes \[\frac{\sigma }{2{{\varepsilon }_{0}}}\] So \[F'=\frac{q\sigma }{2{{\varepsilon }_{0}}}=\frac{F}{2}\]
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